How to solve 5/6 - 7/30 * 3/28

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5/6 - 7/30 * 3/28 | Equatix

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$$\frac{5}{6}-\frac{7}{30}\times\frac{3}{28}$$

$\frac{97}{120}\approx 0.808333333$

Multiply $\frac{7}{30}$ times $\frac{3}{28}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{5}{6}-\frac{7\times 3}{30\times 28}$$

Do the multiplications in the fraction $\frac{7\times 3}{30\times 28}$.

$$\frac{5}{6}-\frac{21}{840}$$

Reduce the fraction $\frac{21}{840}$ to lowest terms by extracting and canceling out $21$.

$$\frac{5}{6}-\frac{1}{40}$$

Least common multiple of $6$ and $40$ is $120$. Convert $\frac{5}{6}$ and $\frac{1}{40}$ to fractions with denominator $120$.

$$\frac{100}{120}-\frac{3}{120}$$

Since $\frac{100}{120}$ and $\frac{3}{120}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{100-3}{120}$$

Subtract $3$ from $100$ to get $97$.

$$\frac{97}{120}$$

$\frac{97}{2 ^ {3} \cdot 3 \cdot 5} = 0.8083333333333333$