How to solve 5/6 + 7/10 + 5/12

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5/6 + 7/10 + 5/12 | Equatix

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Question

$$\frac{5}{6}+\frac{7}{10}+\frac{5}{12}$$

Evaluate

$\frac{39}{20}=1.95$

Solution Steps

Least common multiple of $6$ and $10$ is $30$. Convert $\frac{5}{6}$ and $\frac{7}{10}$ to fractions with denominator $30$.

$$\frac{25}{30}+\frac{21}{30}+\frac{5}{12}$$

Since $\frac{25}{30}$ and $\frac{21}{30}$ have the same denominator, add them by adding their numerators.

$$\frac{25+21}{30}+\frac{5}{12}$$

Add $25$ and $21$ to get $46$.

$$\frac{46}{30}+\frac{5}{12}$$

Reduce the fraction $\frac{46}{30}$ to lowest terms by extracting and canceling out $2$.

$$\frac{23}{15}+\frac{5}{12}$$

Least common multiple of $15$ and $12$ is $60$. Convert $\frac{23}{15}$ and $\frac{5}{12}$ to fractions with denominator $60$.

$$\frac{92}{60}+\frac{25}{60}$$

Since $\frac{92}{60}$ and $\frac{25}{60}$ have the same denominator, add them by adding their numerators.

$$\frac{92+25}{60}$$

Add $92$ and $25$ to get $117$.

$$\frac{117}{60}$$

Reduce the fraction $\frac{117}{60}$ to lowest terms by extracting and canceling out $3$.

$$\frac{39}{20}$$

Show Solution

Factor

$\frac{3 \cdot 13}{2 ^ {2} \cdot 5} = 1\frac{19}{20} = 1.95$