How to solve 5/6 + 7/8

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5/6 + 7/8 | Equatix

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$$\frac{5}{6}+\frac{7}{8}$$

$\frac{41}{24}\approx 1.708333333$

Least common multiple of $6$ and $8$ is $24$. Convert $\frac{5}{6}$ and $\frac{7}{8}$ to fractions with denominator $24$.

$$\frac{20}{24}+\frac{21}{24}$$

Since $\frac{20}{24}$ and $\frac{21}{24}$ have the same denominator, add them by adding their numerators.

$$\frac{20+21}{24}$$

Add $20$ and $21$ to get $41$.

$$\frac{41}{24}$$

$\frac{41}{2 ^ {3} \cdot 3} = 1\frac{17}{24} = 1.7083333333333333$