How to solve 5/7 * 5/35 =

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5/7 * 5/35 = | Equatix

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$$\frac{5}{7}\cdot\frac{5}{35}=$$

$\frac{5}{49}\approx 0.102040816$

Reduce the fraction $\frac{5}{35}$ to lowest terms by extracting and canceling out $5$.

$$\frac{5}{7}\times \frac{1}{7}$$

Multiply $\frac{5}{7}$ times $\frac{1}{7}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{5\times 1}{7\times 7}$$

Do the multiplications in the fraction $\frac{5\times 1}{7\times 7}$.

$$\frac{5}{49}$$

$\frac{5}{7 ^ {2}} = 0.10204081632653061$