How to solve 5/7 + 7/14 + 8/21

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5/7 + 7/14 + 8/21 | Equatix

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Question

$$\frac{5}{7}+\frac{7}{14}+\frac{8}{21}$$

Evaluate

$\frac{67}{42}\approx 1.595238095$

Solution Steps

Reduce the fraction $\frac{7}{14}$ to lowest terms by extracting and canceling out $7$.

$$\frac{5}{7}+\frac{1}{2}+\frac{8}{21}$$

Least common multiple of $7$ and $2$ is $14$. Convert $\frac{5}{7}$ and $\frac{1}{2}$ to fractions with denominator $14$.

$$\frac{10}{14}+\frac{7}{14}+\frac{8}{21}$$

Since $\frac{10}{14}$ and $\frac{7}{14}$ have the same denominator, add them by adding their numerators.

$$\frac{10+7}{14}+\frac{8}{21}$$

Add $10$ and $7$ to get $17$.

$$\frac{17}{14}+\frac{8}{21}$$

Least common multiple of $14$ and $21$ is $42$. Convert $\frac{17}{14}$ and $\frac{8}{21}$ to fractions with denominator $42$.

$$\frac{51}{42}+\frac{16}{42}$$

Since $\frac{51}{42}$ and $\frac{16}{42}$ have the same denominator, add them by adding their numerators.

$$\frac{51+16}{42}$$

Add $51$ and $16$ to get $67$.

$$\frac{67}{42}$$

Show Solution

Factor

$\frac{67}{2 \cdot 3 \cdot 7} = 1\frac{25}{42} = 1.5952380952380953$