How to solve 5/8 * 4/2 + 7/3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5/8 * 4/2 + 7/3 | Equatix

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Question

$$\frac{5}{8}\times\frac{4}{2}+\frac{7}{3}$$

Evaluate

$\frac{43}{12}\approx 3.583333333$

Solution Steps

Divide $4$ by $2$ to get $2$.

$$\frac{5}{8}\times 2+\frac{7}{3}$$

Express $\frac{5}{8}\times 2$ as a single fraction.

$$\frac{5\times 2}{8}+\frac{7}{3}$$

Multiply $5$ and $2$ to get $10$.

$$\frac{10}{8}+\frac{7}{3}$$

Reduce the fraction $\frac{10}{8}$ to lowest terms by extracting and canceling out $2$.

$$\frac{5}{4}+\frac{7}{3}$$

Least common multiple of $4$ and $3$ is $12$. Convert $\frac{5}{4}$ and $\frac{7}{3}$ to fractions with denominator $12$.

$$\frac{15}{12}+\frac{28}{12}$$

Since $\frac{15}{12}$ and $\frac{28}{12}$ have the same denominator, add them by adding their numerators.

$$\frac{15+28}{12}$$

Add $15$ and $28$ to get $43$.

$$\frac{43}{12}$$

Show Solution

Factor

$\frac{43}{2 ^ {2} \cdot 3} = 3\frac{7}{12} = 3.5833333333333335$