How to solve 5/9 - 4/27 =

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5/9 - 4/27 = | Equatix

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$$\frac{5}{9}-\frac{4}{27}=$$

$\frac{11}{27}\approx 0.407407407$

Least common multiple of $9$ and $27$ is $27$. Convert $\frac{5}{9}$ and $\frac{4}{27}$ to fractions with denominator $27$.

$$\frac{15}{27}-\frac{4}{27}$$

Since $\frac{15}{27}$ and $\frac{4}{27}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{15-4}{27}$$

Subtract $4$ from $15$ to get $11$.

$$\frac{11}{27}$$

$\frac{11}{3 ^ {3}} = 0.4074074074074074$