How to solve (5)/(x2+1)=6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (5)/(x2+1)=6 | Equatix

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$$\frac{ 5 }{ x2+1 } =6$$

$x_{2}=-\frac{1}{6}\approx -0.166666667$

Variable $x_{2}$ cannot be equal to $-1$ since division by zero is not defined. Multiply both sides of the equation by $x_{2}+1$.

$$5=6\left(x_{2}+1\right)$$

Use the distributive property to multiply $6$ by $x_{2}+1$.

$$5=6x_{2}+6$$

Swap sides so that all variable terms are on the left hand side.

$$6x_{2}+6=5$$

Subtract $6$ from both sides.

$$6x_{2}=5-6$$

Subtract $6$ from $5$ to get $-1$.

$$6x_{2}=-1$$

Divide both sides by $6$.

$$x_{2}=\frac{-1}{6}$$

Fraction $\frac{-1}{6}$ can be rewritten as $-\frac{1}{6}$ by extracting the negative sign.

$$x_{2}=-\frac{1}{6}$$