$$\frac { 5 ( 1 - x ) + 3 ( 1 + x ) } { 1 - 2 x } = 8$$
$x=0$
$$5\left(1-x\right)+3\left(1+x\right)=8\left(-2x+1\right)$$
$$5-5x+3\left(1+x\right)=8\left(-2x+1\right)$$
$$5-5x+3+3x=8\left(-2x+1\right)$$
$$8-5x+3x=8\left(-2x+1\right)$$
$$8-2x=8\left(-2x+1\right)$$
$$8-2x=-16x+8$$
$$8-2x+16x=8$$
$$8+14x=8$$
$$14x=8-8$$
$$14x=0$$
$$x=0$$
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