$$\frac{ 5(3-2 \times 1) }{ 4 } + \frac{ 3 \times 1+8 }{ 6 } =3(1+1)$$
$\text{false}$
$$3\times 5\left(3-2\times 1\right)+2\left(3\times 1+8\right)=36\left(1+1\right)$$
$$15\left(3-2\times 1\right)+2\left(3\times 1+8\right)=36\left(1+1\right)$$
$$15\left(3-2\right)+2\left(3\times 1+8\right)=36\left(1+1\right)$$
$$15\times 1+2\left(3\times 1+8\right)=36\left(1+1\right)$$
$$15+2\left(3\times 1+8\right)=36\left(1+1\right)$$
$$15+2\left(3+8\right)=36\left(1+1\right)$$
$$15+2\times 11=36\left(1+1\right)$$
$$15+22=36\left(1+1\right)$$
$$37=36\left(1+1\right)$$
$$37=36\times 2$$
$$37=72$$
$$\text{false}$$
Show Solution
Hide Solution