Question

$$\frac { 5 + 3 } { 8 + 2 } \frac { x ^ { 2 } - 8 x + 1 } { x - 2 } - [ \frac { 0 } { 0 } - 5 \cdot ( - 0 , 0 + x ) + 2 ]$$

Answer

$$f=(4*x)/(Li*m^2*o*r*a*t*x]x*(x-4))$$

Solution


Factor \({x}^{2}-6x+8\).
Cancel \(x-2\).
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
Regroup terms.
Simplify  \(2x\times 2\)  to  \(4x\).
Divide both sides by \(Li\).
Divide both sides by \({m}^{2}\).
Simplify  \(\frac{\frac{4x}{Li}}{{m}^{2}}\)  to  \(\frac{4x}{Li{m}^{2}}\).
Divide both sides by \(o\).
Simplify  \(\frac{\frac{4x}{Li{m}^{2}}}{o}\)  to  \(\frac{4x}{Li{m}^{2}o}\).
Divide both sides by \(r\).
Simplify  \(\frac{\frac{4x}{Li{m}^{2}o}}{r}\)  to  \(\frac{4x}{Li{m}^{2}or}\).
Divide both sides by \(a\).
Simplify  \(\frac{\frac{4x}{Li{m}^{2}or}}{a}\)  to  \(\frac{4x}{Li{m}^{2}ora}\).
Divide both sides by \(t\).
Simplify  \(\frac{\frac{4x}{Li{m}^{2}ora}}{t}\)  to  \(\frac{4x}{Li{m}^{2}orat}\).
Divide both sides by \(x-4\).