Variable $y$ cannot be equal to $-\frac{1}{2}$ since division by zero is not defined. Multiply both sides of the equation by $5\left(2y+1\right)$, the least common multiple of $2y+1,5$.
$$5\left(5y-3\right)=2\left(2y+1\right)$$
Use the distributive property to multiply $5$ by $5y-3$.
$$25y-15=2\left(2y+1\right)$$
Use the distributive property to multiply $2$ by $2y+1$.
