How to solve (5z - 7)/32 = 2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (5z - 7)/32 = 2 | Equatix

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3(r+2s)=2t-4

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3(r+2s)=2t-4

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Question

$$\frac{5z-7}{32}=2$$

Solve for z

$z = \frac{71}{5} = 14\frac{1}{5} = 14.2$

Steps for Solving Linear Equation

Multiply both sides by $32$.

$$5z-7=2\times 32$$

Multiply $2$ and $32$ to get $64$.

$$5z-7=64$$

Add $7$ to both sides.

$$5z=64+7$$

Add $64$ and $7$ to get $71$.

$$5z=71$$

Divide both sides by $5$.

$$z=\frac{71}{5}$$

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Solve for z

Steps for Solving Linear Equation