Question

$$\frac{ 6 { x }^{ 2 } +13x-4 }{ 2x5 } = \frac{ 12 { x }^{ 2 } +5x-2 }{ 4x+3 }$$

Solve for x_5

$x_{5}=-\frac{24x^{3}+70x^{2}+23x-12}{2\left(2-5x-12x^{2}\right)}$
$x\neq -\frac{3}{4}\text{ and }x\neq \frac{\sqrt{265}-13}{12}\text{ and }x\neq \frac{-\sqrt{265}-13}{12}\text{ and }x\neq -\frac{2}{3}\text{ and }x\neq \frac{1}{4}$

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