How to solve (6)/(24)+(3)/(24)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (6)/(24)+(3)/(24) | Equatix

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$$\frac{ 6 }{ 24 } + \frac{ 3 }{ 24 }$$

$\frac{3}{8}=0.375$

Reduce the fraction $\frac{6}{24}$ to lowest terms by extracting and canceling out $6$.

$$\frac{1}{4}+\frac{3}{24}$$

Reduce the fraction $\frac{3}{24}$ to lowest terms by extracting and canceling out $3$.

$$\frac{1}{4}+\frac{1}{8}$$

Least common multiple of $4$ and $8$ is $8$. Convert $\frac{1}{4}$ and $\frac{1}{8}$ to fractions with denominator $8$.

$$\frac{2}{8}+\frac{1}{8}$$

Since $\frac{2}{8}$ and $\frac{1}{8}$ have the same denominator, add them by adding their numerators.

$$\frac{2+1}{8}$$

Add $2$ and $1$ to get $3$.

$$\frac{3}{8}$$

$\frac{3}{2 ^ {3}} = 0.375$