How to solve 6/3 and - 8/39

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6/3 and - 8/39 | Equatix

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$$\frac { 6 } { 3 } \quad \quad \frac { - 8 } { 39 }$$

$-\frac{16}{39}\approx -0.41025641$

Divide $6$ by $3$ to get $2$.

$$2\times \frac{-8}{39}$$

Fraction $\frac{-8}{39}$ can be rewritten as $-\frac{8}{39}$ by extracting the negative sign.

$$2\left(-\frac{8}{39}\right)$$

Express $2\left(-\frac{8}{39}\right)$ as a single fraction.

$$\frac{2\left(-8\right)}{39}$$

Multiply $2$ and $-8$ to get $-16$.

$$\frac{-16}{39}$$

Fraction $\frac{-16}{39}$ can be rewritten as $-\frac{16}{39}$ by extracting the negative sign.

$$-\frac{16}{39}$$

$-\frac{16}{39} = -0.41025641025641024$