How to solve 60 4 4 6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 60 4 4 6 | Equatix

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Question

$$\frac { 6 } { 4 } - \frac { 0 } { 4 } - \frac { 5 } { 6 } - \frac { - 12 } { 6 } =$$

Evaluate

$\frac{8}{3}\approx 2.666666667$

Solution Steps

Reduce the fraction $\frac{6}{4}$ to lowest terms by extracting and canceling out $2$.

$$\frac{3}{2}-\frac{0}{4}-\frac{5}{6}-\frac{-12}{6}$$

Zero divided by any non-zero number gives zero.

$$\frac{3}{2}+0-\frac{5}{6}-\frac{-12}{6}$$

Add $\frac{3}{2}$ and $0$ to get $\frac{3}{2}$.

$$\frac{3}{2}-\frac{5}{6}-\frac{-12}{6}$$

Least common multiple of $2$ and $6$ is $6$. Convert $\frac{3}{2}$ and $\frac{5}{6}$ to fractions with denominator $6$.

$$\frac{9}{6}-\frac{5}{6}-\frac{-12}{6}$$

Since $\frac{9}{6}$ and $\frac{5}{6}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-5}{6}-\frac{-12}{6}$$

Subtract $5$ from $9$ to get $4$.

$$\frac{4}{6}-\frac{-12}{6}$$

Reduce the fraction $\frac{4}{6}$ to lowest terms by extracting and canceling out $2$.

$$\frac{2}{3}-\frac{-12}{6}$$

Divide $-12$ by $6$ to get $-2$.

$$\frac{2}{3}-\left(-2\right)$$

The opposite of $-2$ is $2$.

$$\frac{2}{3}+2$$

Convert $2$ to fraction $\frac{6}{3}$.

$$\frac{2}{3}+\frac{6}{3}$$

Since $\frac{2}{3}$ and $\frac{6}{3}$ have the same denominator, add them by adding their numerators.

$$\frac{2+6}{3}$$

Add $2$ and $6$ to get $8$.

$$\frac{8}{3}$$

Show Solution

Factor

$\frac{2 ^ {3}}{3} = 2\frac{2}{3} = 2.6666666666666665$