Question

$$\frac{ 6 }{ 5 } \times ( \frac{ 2 }{ 3 } + \frac{ 16 }{ 6 } )- \frac{ 6 }{ 5 } +( \frac{ 2 }{ 3 } \times \frac{ 1 }{ 6 } )=$$

Evaluate

$\frac{131}{45}\approx 2.911111111$

Show Solution

Factor

$\frac{131}{3 ^ {2} \cdot 5} = 2\frac{41}{45} = 2.911111111111111$