How to solve 6/5 + 8/3 - 5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6/5 + 8/3 - 5 | Equatix

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$$\frac{6}{5}+\frac{8}{3}-5$$

$-\frac{17}{15}\approx -1.133333333$

Least common multiple of $5$ and $3$ is $15$. Convert $\frac{6}{5}$ and $\frac{8}{3}$ to fractions with denominator $15$.

$$\frac{18}{15}+\frac{40}{15}-5$$

Since $\frac{18}{15}$ and $\frac{40}{15}$ have the same denominator, add them by adding their numerators.

$$\frac{18+40}{15}-5$$

Add $18$ and $40$ to get $58$.

$$\frac{58}{15}-5$$

Convert $5$ to fraction $\frac{75}{15}$.

$$\frac{58}{15}-\frac{75}{15}$$

Since $\frac{58}{15}$ and $\frac{75}{15}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{58-75}{15}$$

Subtract $75$ from $58$ to get $-17$.

$$-\frac{17}{15}$$

$-\frac{17}{15} = -1\frac{2}{15} = -1.1333333333333333$