Solve (6)/(8)-(-2)/(-3)-(-1)/(-3) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac{ 6 }{ 8 } - \frac{ -2 }{ -3 } - \frac{ -1 }{ -3 }$$

Evaluate

$-\frac{1}{4}=-0.25$

Solution Steps

Reduce the fraction $\frac{6}{8}$ to lowest terms by extracting and canceling out $2$.

$$\frac{3}{4}-\frac{-2}{-3}-\frac{-1}{-3}$$

Fraction $\frac{-2}{-3}$ can be simplified to $\frac{2}{3}$ by removing the negative sign from both the numerator and the denominator.

$$\frac{3}{4}-\frac{2}{3}-\frac{-1}{-3}$$

Least common multiple of $4$ and $3$ is $12$. Convert $\frac{3}{4}$ and $\frac{2}{3}$ to fractions with denominator $12$.

$$\frac{9}{12}-\frac{8}{12}-\frac{-1}{-3}$$

Since $\frac{9}{12}$ and $\frac{8}{12}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-8}{12}-\frac{-1}{-3}$$

Subtract $8$ from $9$ to get $1$.

$$\frac{1}{12}-\frac{-1}{-3}$$

Fraction $\frac{-1}{-3}$ can be simplified to $\frac{1}{3}$ by removing the negative sign from both the numerator and the denominator.

$$\frac{1}{12}-\frac{1}{3}$$

Least common multiple of $12$ and $3$ is $12$. Convert $\frac{1}{12}$ and $\frac{1}{3}$ to fractions with denominator $12$.

$$\frac{1}{12}-\frac{4}{12}$$

Since $\frac{1}{12}$ and $\frac{4}{12}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-4}{12}$$

Subtract $4$ from $1$ to get $-3$.

$$\frac{-3}{12}$$

Reduce the fraction $\frac{-3}{12}$ to lowest terms by extracting and canceling out $3$.

$$-\frac{1}{4}$$

Factor

$-\frac{1}{4} = -0.25$