$$\frac{ 6 }{ \sqrt{ 3 } } -2 \sqrt{ 2 } - \frac{ 5 \sqrt{ 3 } }{ 4 }$$
$\frac{3\sqrt{3}}{4}-2\sqrt{2}\approx -1.529389019$
$$\frac{6\sqrt{3}}{\left(\sqrt{3}\right)^{2}}-2\sqrt{2}-\frac{5\sqrt{3}}{4}$$
$$\frac{6\sqrt{3}}{3}-2\sqrt{2}-\frac{5\sqrt{3}}{4}$$
$$2\sqrt{3}-2\sqrt{2}-\frac{5\sqrt{3}}{4}$$
$$\frac{3}{4}\sqrt{3}-2\sqrt{2}$$
Show Solution
Hide Solution
$\frac{3 \sqrt{3} - 8 \sqrt{2}}{4} = -1.5293890190695323$