How to solve (6)/(x+5)=-5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (6)/(x+5)=-5 | Equatix

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$$\frac{ 6 }{ x+5 } =-5$$

$x = -\frac{31}{5} = -6\frac{1}{5} = -6.2$

Variable $x$ cannot be equal to $-5$ since division by zero is not defined. Multiply both sides of the equation by $x+5$.

$$6=-5\left(x+5\right)$$

Use the distributive property to multiply $-5$ by $x+5$.

$$6=-5x-25$$

Swap sides so that all variable terms are on the left hand side.

$$-5x-25=6$$

Add $25$ to both sides.

$$-5x=6+25$$

Add $6$ and $25$ to get $31$.

$$-5x=31$$

Divide both sides by $-5$.

$$x=\frac{31}{-5}$$

Fraction $\frac{31}{-5}$ can be rewritten as $-\frac{31}{5}$ by extracting the negative sign.

$$x=-\frac{31}{5}$$