$$\frac{6x+1}{3}+1=\frac{x-3}{6}$$
$x=-1$
$$2\left(6x+1\right)+6=x-3$$
$$12x+2+6=x-3$$
$$12x+8=x-3$$
$$12x+8-x=-3$$
$$11x+8=-3$$
$$11x=-3-8$$
$$11x=-11$$
$$x=\frac{-11}{11}$$
$$x=-1$$
Show Solution
Hide Solution