Question

$$\frac{6x+1}{3}+\frac{1}{.}=\frac{x-3}{6}$$

Answer

x=(-49-1.)/5

Solution


Subtract \(1.\) from both sides.
\[6x+13=x-36-1.\]
Subtract \(x\) from both sides.
\[6x+13-x=-36-1.\]
Simplify  \(6x+13-x\)  to  \(5x+13\).
\[5x+13=-36-1.\]
Subtract \(13\) from both sides.
\[5x=-36-1.-13\]
Simplify  \(-36-1.\)  to  \(-36-1.\).
\[5x=-49-1.\]
Divide both sides by \(5\).
\[x=\frac{-49-1.}{5}\]