$$\frac{6x^{2}-3x}{4-8x}$$
$-\frac{3x}{4}$
$$\frac{3x\left(2x-1\right)}{4\left(-2x+1\right)}$$
$$\frac{-3x\left(-2x+1\right)}{4\left(-2x+1\right)}$$
$$\frac{-3x}{4}$$
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