Question

$$\frac { 7 , 8 - 11 , 7 : 0 , 5 } { ( \frac { 1 } { 2 } + \frac { 1 } { 3 } + \frac { 1 } { 4 } ) \cdot \frac { 12 } { 13 } }$$

Answer

6*(7,-3,7/6,5)

Solution


Simplify  \(8-11\)  to  \(-3\).
\[6\times \frac{7,-3,\frac{7}{6},5}{(\frac{1}{2}+\frac{1}{3}+\frac{1}{4})\times \frac{12}{13}}\]
Simplify  \(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\)  to  \(\frac{13}{12}\).
\[6\times \frac{7,-3,\frac{7}{6},5}{\frac{13}{12}\times \frac{12}{13}}\]
Cancel \(12\).
\[6\times \frac{7,-3,\frac{7}{6},5}{13\times \frac{1}{13}}\]
Cancel \(13\).
\[6\times \frac{7,-3,\frac{7}{6},5}{1}\]
Simplify.
\[6(7,-3,\frac{7}{6},5)\]