Question

$$\frac { 7 , 8 - 11 , 7 : 6 , 5 } { ( \frac { 1 } { 2 } + \frac { 1 } { 3 } + \frac { 1 } { 4 } ) \cdot \frac { 12 } { 13 } }$$

Answer

6*(7,-3,1.0769230769231)

Solution


Simplify  \(\frac{7}{6.5}\)  to  \(1.076923\).
\[6\times \frac{7,8-11,1.076923}{(\frac{1}{2}+\frac{1}{3}+\frac{1}{4})\times \frac{12}{13}}\]
Simplify  \(8-11\)  to  \(-3\).
\[6\times \frac{7,-3,1.076923}{(\frac{1}{2}+\frac{1}{3}+\frac{1}{4})\times \frac{12}{13}}\]
Simplify  \(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\)  to  \(\frac{13}{12}\).
\[6\times \frac{7,-3,1.076923}{\frac{13}{12}\times \frac{12}{13}}\]
Cancel \(12\).
\[6\times \frac{7,-3,1.076923}{13\times \frac{1}{13}}\]
Cancel \(13\).
\[6\times \frac{7,-3,1.076923}{1}\]
Use this rule: \(a \times \frac{b}{c}=\frac{ab}{c}\).
\[6\times (7,-3,1.076923)\]