How to solve 7/10 - 1/2 =

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/10 - 1/2 = | Equatix

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$$\frac{7}{10}-\frac{1}{2}=$$

$\frac{1}{5}=0.2$

Least common multiple of $10$ and $2$ is $10$. Convert $\frac{7}{10}$ and $\frac{1}{2}$ to fractions with denominator $10$.

$$\frac{7}{10}-\frac{5}{10}$$

Since $\frac{7}{10}$ and $\frac{5}{10}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{7-5}{10}$$

Subtract $5$ from $7$ to get $2$.

$$\frac{2}{10}$$

Reduce the fraction $\frac{2}{10}$ to lowest terms by extracting and canceling out $2$.

$$\frac{1}{5}$$

$\frac{1}{5} = 0.2$