How to solve 7/10 - 2/15

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/10 - 2/15 | Equatix

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$$\frac{7}{10}-\frac{2}{15}$$

$\frac{17}{30}\approx 0.566666667$

Least common multiple of $10$ and $15$ is $30$. Convert $\frac{7}{10}$ and $\frac{2}{15}$ to fractions with denominator $30$.

$$\frac{21}{30}-\frac{4}{30}$$

Since $\frac{21}{30}$ and $\frac{4}{30}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{21-4}{30}$$

Subtract $4$ from $21$ to get $17$.

$$\frac{17}{30}$$

$\frac{17}{2 \cdot 3 \cdot 5} = 0.5666666666666667$