How to solve 7/10 - 3/2 * 5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/10 - 3/2 * 5 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

$$\frac{7}{10}-\frac{3}{2}\times5$$

$-\frac{34}{5}=-6.8$

Express $\frac{3}{2}\times 5$ as a single fraction.

$$\frac{7}{10}-\frac{3\times 5}{2}$$

Multiply $3$ and $5$ to get $15$.

$$\frac{7}{10}-\frac{15}{2}$$

Least common multiple of $10$ and $2$ is $10$. Convert $\frac{7}{10}$ and $\frac{15}{2}$ to fractions with denominator $10$.

$$\frac{7}{10}-\frac{75}{10}$$

Since $\frac{7}{10}$ and $\frac{75}{10}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{7-75}{10}$$

Subtract $75$ from $7$ to get $-68$.

$$\frac{-68}{10}$$

Reduce the fraction $\frac{-68}{10}$ to lowest terms by extracting and canceling out $2$.

$$-\frac{34}{5}$$

$-\frac{34}{5} = -6\frac{4}{5} = -6.8$