1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$\frac { 7 } { 10 } + \frac { 2 } { 8 }$$

$\frac{19}{20}=0.95$

Reduce the fraction $\frac{2}{8}$ to lowest terms by extracting and canceling out $2$.

$$\frac{7}{10}+\frac{1}{4}$$

Least common multiple of $10$ and $4$ is $20$. Convert $\frac{7}{10}$ and $\frac{1}{4}$ to fractions with denominator $20$.

$$\frac{14}{20}+\frac{5}{20}$$

Since $\frac{14}{20}$ and $\frac{5}{20}$ have the same denominator, add them by adding their numerators.

$$\frac{14+5}{20}$$

Add $14$ and $5$ to get $19$.

$$\frac{19}{20}$$

$\frac{19}{2 ^ {2} \cdot 5} = 0.95$