How to solve 7/11 - 3/7

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/11 - 3/7 | Equatix

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$$\frac{7}{11}+\frac{-3}{7}$$

$\frac{16}{77}\approx 0.207792208$

Fraction $\frac{-3}{7}$ can be rewritten as $-\frac{3}{7}$ by extracting the negative sign.

$$\frac{7}{11}-\frac{3}{7}$$

Least common multiple of $11$ and $7$ is $77$. Convert $\frac{7}{11}$ and $\frac{3}{7}$ to fractions with denominator $77$.

$$\frac{49}{77}-\frac{33}{77}$$

Since $\frac{49}{77}$ and $\frac{33}{77}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{49-33}{77}$$

Subtract $33$ from $49$ to get $16$.

$$\frac{16}{77}$$

$\frac{2 ^ {4}}{7 \cdot 11} = 0.2077922077922078$