How to solve 7/12 + 3/6 + 4/2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/12 + 3/6 + 4/2 | Equatix

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Question

$$\frac{7}{12}+\frac{3}{6}+\frac{4}{2}$$

Evaluate

$\frac{37}{12}\approx 3.083333333$

Solution Steps

Reduce the fraction $\frac{3}{6}$ to lowest terms by extracting and canceling out $3$.

$$\frac{7}{12}+\frac{1}{2}+\frac{4}{2}$$

Least common multiple of $12$ and $2$ is $12$. Convert $\frac{7}{12}$ and $\frac{1}{2}$ to fractions with denominator $12$.

$$\frac{7}{12}+\frac{6}{12}+\frac{4}{2}$$

Since $\frac{7}{12}$ and $\frac{6}{12}$ have the same denominator, add them by adding their numerators.

$$\frac{7+6}{12}+\frac{4}{2}$$

Add $7$ and $6$ to get $13$.

$$\frac{13}{12}+\frac{4}{2}$$

Divide $4$ by $2$ to get $2$.

$$\frac{13}{12}+2$$

Convert $2$ to fraction $\frac{24}{12}$.

$$\frac{13}{12}+\frac{24}{12}$$

Since $\frac{13}{12}$ and $\frac{24}{12}$ have the same denominator, add them by adding their numerators.

$$\frac{13+24}{12}$$

Add $13$ and $24$ to get $37$.

$$\frac{37}{12}$$

Show Solution

Factor

$\frac{37}{2 ^ {2} \cdot 3} = 3\frac{1}{12} = 3.0833333333333335$