How to solve 7/12 + 5/6 + 3/8

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/12 + 5/6 + 3/8 | Equatix

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$$\frac{7}{12}+\frac{5}{6}+\frac{3}{8}$$

$\frac{43}{24}\approx 1.791666667$

Least common multiple of $12$ and $6$ is $12$. Convert $\frac{7}{12}$ and $\frac{5}{6}$ to fractions with denominator $12$.

$$\frac{7}{12}+\frac{10}{12}+\frac{3}{8}$$

Since $\frac{7}{12}$ and $\frac{10}{12}$ have the same denominator, add them by adding their numerators.

$$\frac{7+10}{12}+\frac{3}{8}$$

Add $7$ and $10$ to get $17$.

$$\frac{17}{12}+\frac{3}{8}$$

Least common multiple of $12$ and $8$ is $24$. Convert $\frac{17}{12}$ and $\frac{3}{8}$ to fractions with denominator $24$.

$$\frac{34}{24}+\frac{9}{24}$$

Since $\frac{34}{24}$ and $\frac{9}{24}$ have the same denominator, add them by adding their numerators.

$$\frac{34+9}{24}$$

Add $34$ and $9$ to get $43$.

$$\frac{43}{24}$$

$\frac{43}{2 ^ {3} \cdot 3} = 1\frac{19}{24} = 1.7916666666666667$