Solve 7 130 *2\%+560 | Equatix

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Question

$$\frac{7}{130}\times2\%+560$$

$\frac{3640007}{6500}\approx 560.001076923$

Reduce the fraction $\frac{2}{100}$ to lowest terms by extracting and canceling out $2$.

$$\frac{7}{130}\times \frac{1}{50}+560$$

Multiply $\frac{7}{130}$ times $\frac{1}{50}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\times 1}{130\times 50}+560$$

Do the multiplications in the fraction $\frac{7\times 1}{130\times 50}$.

$$\frac{7}{6500}+560$$

Convert $560$ to fraction $\frac{3640000}{6500}$.

$$\frac{7}{6500}+\frac{3640000}{6500}$$

Since $\frac{7}{6500}$ and $\frac{3640000}{6500}$ have the same denominator, add them by adding their numerators.

$$\frac{7+3640000}{6500}$$

Add $7$ and $3640000$ to get $3640007$.

$$\frac{3640007}{6500}$$

$\frac{7 \cdot 331 \cdot 1571}{2 ^ {2} \cdot 5 ^ {3} \cdot 13} = 560\frac{7}{6500} = 560.0010769230769$