$$\frac{ 7 }{ 15 } y+3= \frac{ 2 }{ 15 } 4+6$$
$y = \frac{53}{7} = 7\frac{4}{7} \approx 7.571428571$
$$\frac{7}{15}y+3=\frac{2\times 4}{15}+6$$
$$\frac{7}{15}y+3=\frac{8}{15}+6$$
$$\frac{7}{15}y+3=\frac{8}{15}+\frac{90}{15}$$
$$\frac{7}{15}y+3=\frac{8+90}{15}$$
$$\frac{7}{15}y+3=\frac{98}{15}$$
$$\frac{7}{15}y=\frac{98}{15}-3$$
$$\frac{7}{15}y=\frac{98}{15}-\frac{45}{15}$$
$$\frac{7}{15}y=\frac{98-45}{15}$$
$$\frac{7}{15}y=\frac{53}{15}$$
$$y=\frac{53}{15}\times \frac{15}{7}$$
$$y=\frac{53\times 15}{15\times 7}$$
$$y=\frac{53}{7}$$
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