How to solve 7/27 / (49/81)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/27 / (49/81) | Equatix

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$$\frac{7}{27}\div\frac{49}{81}$$

$\frac{3}{7}\approx 0.428571429$

Divide $\frac{7}{27}$ by $\frac{49}{81}$ by multiplying $\frac{7}{27}$ by the reciprocal of $\frac{49}{81}$.

$$\frac{7}{27}\times \frac{81}{49}$$

Multiply $\frac{7}{27}$ times $\frac{81}{49}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\times 81}{27\times 49}$$

Do the multiplications in the fraction $\frac{7\times 81}{27\times 49}$.

$$\frac{567}{1323}$$

Reduce the fraction $\frac{567}{1323}$ to lowest terms by extracting and canceling out $189$.

$$\frac{3}{7}$$

$\frac{3}{7} = 0.42857142857142855$