How to solve 7/3 - 1/4

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/3 - 1/4 | Equatix

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$$\frac{7}{3}-\frac{1}{4}$$

$\frac{25}{12}\approx 2.083333333$

Least common multiple of $3$ and $4$ is $12$. Convert $\frac{7}{3}$ and $\frac{1}{4}$ to fractions with denominator $12$.

$$\frac{28}{12}-\frac{3}{12}$$

Since $\frac{28}{12}$ and $\frac{3}{12}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{28-3}{12}$$

Subtract $3$ from $28$ to get $25$.

$$\frac{25}{12}$$

$\frac{5 ^ {2}}{2 ^ {2} \cdot 3} = 2\frac{1}{12} = 2.0833333333333335$