Solve 7/3 - 7/9 = - 7/9 + 7/3 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac{7}{3}+\frac{-7}{9}=\frac{-7}{9}+\frac{7}{3}$$

Verify

$\text{true}$

Solution Steps

Fraction $\frac{-7}{9}$ can be rewritten as $-\frac{7}{9}$ by extracting the negative sign.

$$\frac{7}{3}-\frac{7}{9}=\frac{-7}{9}+\frac{7}{3}$$

Least common multiple of $3$ and $9$ is $9$. Convert $\frac{7}{3}$ and $\frac{7}{9}$ to fractions with denominator $9$.

$$\frac{21}{9}-\frac{7}{9}=\frac{-7}{9}+\frac{7}{3}$$

Since $\frac{21}{9}$ and $\frac{7}{9}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{21-7}{9}=\frac{-7}{9}+\frac{7}{3}$$

Subtract $7$ from $21$ to get $14$.

$$\frac{14}{9}=\frac{-7}{9}+\frac{7}{3}$$

Fraction $\frac{-7}{9}$ can be rewritten as $-\frac{7}{9}$ by extracting the negative sign.

$$\frac{14}{9}=-\frac{7}{9}+\frac{7}{3}$$

Least common multiple of $9$ and $3$ is $9$. Convert $-\frac{7}{9}$ and $\frac{7}{3}$ to fractions with denominator $9$.

$$\frac{14}{9}=-\frac{7}{9}+\frac{21}{9}$$

Since $-\frac{7}{9}$ and $\frac{21}{9}$ have the same denominator, add them by adding their numerators.

$$\frac{14}{9}=\frac{-7+21}{9}$$

Add $-7$ and $21$ to get $14$.

$$\frac{14}{9}=\frac{14}{9}$$

Compare $\frac{14}{9}$ and $\frac{14}{9}$.

$$\text{true}$$