How to solve * 7 4 - 13 28 +

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve * 7 4 - 13 28 + | Equatix

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$$\frac { 7 } { 4 } - \frac { 13 } { 28 }$$

$\frac{9}{7}\approx 1.285714286$

Least common multiple of $4$ and $28$ is $28$. Convert $\frac{7}{4}$ and $\frac{13}{28}$ to fractions with denominator $28$.

$$\frac{49}{28}-\frac{13}{28}$$

Since $\frac{49}{28}$ and $\frac{13}{28}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{49-13}{28}$$

Subtract $13$ from $49$ to get $36$.

$$\frac{36}{28}$$

Reduce the fraction $\frac{36}{28}$ to lowest terms by extracting and canceling out $4$.

$$\frac{9}{7}$$

$\frac{3 ^ {2}}{7} = 1\frac{2}{7} = 1.2857142857142858$