How to solve 7/4 + 8/9 + 1/3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/4 + 8/9 + 1/3 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

$$\frac{7}{4}+\frac{8}{9}+\frac{1}{3}$$

$\frac{107}{36}\approx 2.972222222$

Least common multiple of $4$ and $9$ is $36$. Convert $\frac{7}{4}$ and $\frac{8}{9}$ to fractions with denominator $36$.

$$\frac{63}{36}+\frac{32}{36}+\frac{1}{3}$$

Since $\frac{63}{36}$ and $\frac{32}{36}$ have the same denominator, add them by adding their numerators.

$$\frac{63+32}{36}+\frac{1}{3}$$

Add $63$ and $32$ to get $95$.

$$\frac{95}{36}+\frac{1}{3}$$

Least common multiple of $36$ and $3$ is $36$. Convert $\frac{95}{36}$ and $\frac{1}{3}$ to fractions with denominator $36$.

$$\frac{95}{36}+\frac{12}{36}$$

Since $\frac{95}{36}$ and $\frac{12}{36}$ have the same denominator, add them by adding their numerators.

$$\frac{95+12}{36}$$

Add $95$ and $12$ to get $107$.

$$\frac{107}{36}$$

$\frac{107}{2 ^ {2} \cdot 3 ^ {2}} = 2\frac{35}{36} = 2.9722222222222223$