How to solve 7/42 + 3/28 =

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/42 + 3/28 = | Equatix

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$$\frac{7}{42}+\frac{3}{28}=$$

$\frac{23}{84}\approx 0.273809524$

Reduce the fraction $\frac{7}{42}$ to lowest terms by extracting and canceling out $7$.

$$\frac{1}{6}+\frac{3}{28}$$

Least common multiple of $6$ and $28$ is $84$. Convert $\frac{1}{6}$ and $\frac{3}{28}$ to fractions with denominator $84$.

$$\frac{14}{84}+\frac{9}{84}$$

Since $\frac{14}{84}$ and $\frac{9}{84}$ have the same denominator, add them by adding their numerators.

$$\frac{14+9}{84}$$

Add $14$ and $9$ to get $23$.

$$\frac{23}{84}$$

$\frac{23}{2 ^ {2} \cdot 3 \cdot 7} = 0.27380952380952384$