How to solve 7/5 + x = 5/7

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/5 + x = 5/7 | Equatix

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$$\frac{7}{5}+x=\frac{5}{7}$$

$x=-\frac{24}{35}\approx -0.685714286$

Subtract $\frac{7}{5}$ from both sides.

$$x=\frac{5}{7}-\frac{7}{5}$$

Least common multiple of $7$ and $5$ is $35$. Convert $\frac{5}{7}$ and $\frac{7}{5}$ to fractions with denominator $35$.

$$x=\frac{25}{35}-\frac{49}{35}$$

Since $\frac{25}{35}$ and $\frac{49}{35}$ have the same denominator, subtract them by subtracting their numerators.

$$x=\frac{25-49}{35}$$

Subtract $49$ from $25$ to get $-24$.

$$x=-\frac{24}{35}$$