How to solve 7/8 - 1/12

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/8 - 1/12 | Equatix

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$$\frac{7}{8}-\frac{1}{12}$$

$\frac{19}{24}\approx 0.791666667$

Least common multiple of $8$ and $12$ is $24$. Convert $\frac{7}{8}$ and $\frac{1}{12}$ to fractions with denominator $24$.

$$\frac{21}{24}-\frac{2}{24}$$

Since $\frac{21}{24}$ and $\frac{2}{24}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{21-2}{24}$$

Subtract $2$ from $21$ to get $19$.

$$\frac{19}{24}$$

$\frac{19}{2 ^ {3} \cdot 3} = 0.7916666666666666$