Solve (7)/(8)-(3)/(5)\div(1)/(4)= | Equatix

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Question

$$\frac{ 7 }{ 8 } - \frac{ 3 }{ 5 } \div \frac{ 1 }{ 4 } =$$

$-\frac{61}{40}=-1.525$

Divide $\frac{3}{5}$ by $\frac{1}{4}$ by multiplying $\frac{3}{5}$ by the reciprocal of $\frac{1}{4}$.

$$\frac{7}{8}-\frac{3}{5}\times 4$$

Express $\frac{3}{5}\times 4$ as a single fraction.

$$\frac{7}{8}-\frac{3\times 4}{5}$$

Multiply $3$ and $4$ to get $12$.

$$\frac{7}{8}-\frac{12}{5}$$

Least common multiple of $8$ and $5$ is $40$. Convert $\frac{7}{8}$ and $\frac{12}{5}$ to fractions with denominator $40$.

$$\frac{35}{40}-\frac{96}{40}$$

Since $\frac{35}{40}$ and $\frac{96}{40}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{35-96}{40}$$

Subtract $96$ from $35$ to get $-61$.

$$-\frac{61}{40}$$

$-\frac{61}{40} = -1\frac{21}{40} = -1.525$