Solve 7/8 - 1/7 = - 1/7 + 17/8 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac{7}{8}+\frac{-1}{7}=\frac{-1}{7}+\frac{17}{8}$$

Verify

$\text{false}$

Solution Steps

Fraction $\frac{-1}{7}$ can be rewritten as $-\frac{1}{7}$ by extracting the negative sign.

$$\frac{7}{8}-\frac{1}{7}=\frac{-1}{7}+\frac{17}{8}$$

Least common multiple of $8$ and $7$ is $56$. Convert $\frac{7}{8}$ and $\frac{1}{7}$ to fractions with denominator $56$.

$$\frac{49}{56}-\frac{8}{56}=\frac{-1}{7}+\frac{17}{8}$$

Since $\frac{49}{56}$ and $\frac{8}{56}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{49-8}{56}=\frac{-1}{7}+\frac{17}{8}$$

Subtract $8$ from $49$ to get $41$.

$$\frac{41}{56}=\frac{-1}{7}+\frac{17}{8}$$

Fraction $\frac{-1}{7}$ can be rewritten as $-\frac{1}{7}$ by extracting the negative sign.

$$\frac{41}{56}=-\frac{1}{7}+\frac{17}{8}$$

Least common multiple of $7$ and $8$ is $56$. Convert $-\frac{1}{7}$ and $\frac{17}{8}$ to fractions with denominator $56$.

$$\frac{41}{56}=-\frac{8}{56}+\frac{119}{56}$$

Since $-\frac{8}{56}$ and $\frac{119}{56}$ have the same denominator, add them by adding their numerators.

$$\frac{41}{56}=\frac{-8+119}{56}$$

Add $-8$ and $119$ to get $111$.

$$\frac{41}{56}=\frac{111}{56}$$

Compare $\frac{41}{56}$ and $\frac{111}{56}$.

$$\text{false}$$