$$\frac{7}{8}+(\frac{2}{3}-(\frac{1}{3})^{2})$$
$\frac{103}{72}\approx 1.430555556$
$$\frac{7}{8}+\frac{2}{3}-\frac{1}{9}$$
$$\frac{7}{8}+\frac{6}{9}-\frac{1}{9}$$
$$\frac{7}{8}+\frac{6-1}{9}$$
$$\frac{7}{8}+\frac{5}{9}$$
$$\frac{63}{72}+\frac{40}{72}$$
$$\frac{63+40}{72}$$
$$\frac{103}{72}$$
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$\frac{103}{2 ^ {3} \cdot 3 ^ {2}} = 1\frac{31}{72} = 1.4305555555555556$
