How to solve (7)/(8)x(49)/(56)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (7)/(8)x(49)/(56) | Equatix

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Question

$$\frac{ 7 }{ 8 } x \frac{ 49 }{ 56 }$$

Evaluate

$\frac{49x}{64}$

Solution Steps

Reduce the fraction $\frac{49}{56}$ to lowest terms by extracting and canceling out $7$.

$$\frac{7}{8}x\times \frac{7}{8}$$

Multiply $\frac{7}{8}$ times $\frac{7}{8}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\times 7}{8\times 8}x$$

Do the multiplications in the fraction $\frac{7\times 7}{8\times 8}$.

$$\frac{49}{64}x$$

Show Solution

Differentiate w.r.t. x

$\frac{49}{64} = 0.765625$

Steps Using Definition of a Derivative

Reduce the fraction $\frac{49}{56}$ to lowest terms by extracting and canceling out $7$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{7}{8}x\times \frac{7}{8})$$

Multiply $\frac{7}{8}$ times $\frac{7}{8}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{7\times 7}{8\times 8}x)$$

Do the multiplications in the fraction $\frac{7\times 7}{8\times 8}$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{49}{64}x)$$

The derivative of $ax^{n}$ is $nax^{n-1}$.

$$\frac{49}{64}x^{1-1}$$

Subtract $1$ from $1$.

$$\frac{49}{64}x^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$\frac{49}{64}\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$\frac{49}{64}$$