How to solve 7/9 - 3/4 + 4/7

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/9 - 3/4 + 4/7 | Equatix

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$$\frac{7}{9}-\frac{3}{4}+\frac{4}{7}$$

$\frac{151}{252}\approx 0.599206349$

Least common multiple of $9$ and $4$ is $36$. Convert $\frac{7}{9}$ and $\frac{3}{4}$ to fractions with denominator $36$.

$$\frac{28}{36}-\frac{27}{36}+\frac{4}{7}$$

Since $\frac{28}{36}$ and $\frac{27}{36}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{28-27}{36}+\frac{4}{7}$$

Subtract $27$ from $28$ to get $1$.

$$\frac{1}{36}+\frac{4}{7}$$

Least common multiple of $36$ and $7$ is $252$. Convert $\frac{1}{36}$ and $\frac{4}{7}$ to fractions with denominator $252$.

$$\frac{7}{252}+\frac{144}{252}$$

Since $\frac{7}{252}$ and $\frac{144}{252}$ have the same denominator, add them by adding their numerators.

$$\frac{7+144}{252}$$

Add $7$ and $144$ to get $151$.

$$\frac{151}{252}$$

$\frac{151}{2 ^ {2} \cdot 3 ^ {2} \cdot 7} = 0.5992063492063492$