How to solve 7/9 - 3/9 - 1/9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/9 - 3/9 - 1/9 | Equatix

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$$\frac{7}{9}-\frac{3}{9}-\frac{1}{9}$$

$\frac{1}{3}\approx 0.333333333$

Since $\frac{7}{9}$ and $\frac{3}{9}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{7-3}{9}-\frac{1}{9}$$

Subtract $3$ from $7$ to get $4$.

$$\frac{4}{9}-\frac{1}{9}$$

Since $\frac{4}{9}$ and $\frac{1}{9}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{4-1}{9}$$

Subtract $1$ from $4$ to get $3$.

$$\frac{3}{9}$$

Reduce the fraction $\frac{3}{9}$ to lowest terms by extracting and canceling out $3$.

$$\frac{1}{3}$$

$\frac{1}{3} = 0.3333333333333333$